a11an2an的甄选

问题详情：已知数列{an}满足:a1=1,an=+2an-1(n≥2),若bn=(n∈N*),则数列{bn}的前n项和Sn=. 【回答】1-当n≥2时,an+1=+2an-1+1=(an-1+1)2>0,两边取以2为底的对数可得log2(an+1)=log2(an-1+1)2=2log2(an-1+1),则数列{lo...